Worked solution
- W=10×3=30 J.
Calculate work done, changes in gravitational and kinetic energy, and power in everyday systems.
12 free questions · Notes · Worked solutions
Work done by a constant force parallel to motion is W=Fd. Work done transfers energy, so work and energy are measured in joules. If force is not parallel, use the component along the displacement.
Gravitational potential energy change is ΔEₚ=mgΔh. Kinetic energy is Eₖ=½mv². Use mass in kilograms and speed in metres per second.
Power is the rate of energy transfer: P=E/t, measured in watts. Efficiency=useful output energy/total input energy; multiply by 100 for a percentage.
Doubling speed quadruples kinetic energy. A higher object has more gravitational potential energy relative to the chosen reference level. Do not confuse energy (J) with power (W).
A 2 kg book is lifted vertically by 3 m. Using g=10 N/kg, find the gain in gravitational potential energy. If the lift takes 2 s, find the average power.
60 J; 30 W
These are original practice questions, not official past-paper questions. Practice points count correct final answers; working is not automatically assessed.
Selected IGCSE concepts, with a mix of introductory and more demanding questions. Check your own specification. AI drafted; independent teacher review is pending. Editorial details.
Cambridge IGCSE Physics 0625 syllabus